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A box contains 3 blue, 2 white and 4 red marbles. One marble is drawn at random. What is the probability that the marble is not white?
A$\frac{2}{9}$
B$\frac{5}{9}$
C$\frac{7}{9}$
D$\frac{4}{9}$
Answer & Solution
Correct answer: C. $\frac{7}{9}$
The total number of marbles is $3+2+4=9$. 'Not white' means blue or red, so favourable outcomes are $3+4=7$. Therefore the probability is $\frac{7}{9}$.
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