The sum of the first 10 odd natural numbers (1 + 3 + 5 + … + 19) is:

Question

Accepted Answer

D. {'text': '100'}

1. The identity: sum of first n odd numbers = n².
2. Here n = 10, so the sum is 10² = 100.
3. Direct: 1+3+5+7+9+11+13+15+17+19 = 100 ✓.
4. Hence the answer is **100**.
_Source: Selina Concise ICSE Class 8 Mathematics Ch 3 "Squares and Square Roots", Sum of odd numbers property_

Answer

{'text': '81'}

Answer

{'text': '90'}

Answer

{'text': '121'}