Two resistors R₁ and R₂ in PARALLEL have equivalent resistance:
AR₁ + R₂ sum directly
BR₁ R₂ / (R₁ + R₂)
C(R₁ + R₂) / 2 mean
DR₁ − R₂ difference
Answer & Solution
Correct answer: B. R₁ R₂ / (R₁ + R₂)
1. Same V across both; currents add.
2. 1/R_eq = 1/R₁ + 1/R₂ ⇒ R_eq = R₁ R₂ / (R₁ + R₂).
3. R_eq is always LESS than the smallest resistor in the parallel combination.
_Source: NCERT Class 12 Physics Ch 3 §3.10 Series and Parallel_
Related questions
The reactance of a capacitor $C$ at frequency $f$ in an a.c. circuit is:A bird perched on a single high voltage wire is unharmed because:The two conservation laws embodied in Kirchhoff's rules are conservation of:The resistance offered by the cell itself is called:Which device detects the current in a Wheatstone bridge?In a Wheatstone bridge, the source is connected across the:The Wheatstone bridge is made up of how many resistors?At a junction, the current entering equals the current: