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For N₂ + 3H₂ ⇌ 2NH₃, increasing the total pressure shifts the equilibrium:

ATowards the reactants
BReaction stops here
CNo shift either way
DTowards the products
Answer & Solution
Correct answer: D. Towards the products
1. Apply Le Chatelier: a pressure increase favours the side with FEWER moles of gas. 2. Left side has 4 moles (1 + 3) of gas, right has 2 (NH₃). 3. So equilibrium shifts towards products (NH₃ formation). 4. This is why the Haber process runs at high pressure. _Source: syllabus Chem Ch 7 §7.6 Factors Affecting Equilibrium_
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