alleryPressure at depth h below the free surface of a liquid of density ρ (with atmospheric pressure P₀ above) is:
AP₀ + ρ g h
BP₀ − ρ g h
Cρ g h
DP₀ · ρ g h
Answer & Solution
Correct answer: A. P₀ + ρ g h
1. Pressure increases linearly with depth: dP/dh = ρ g.
2. Integrating from the free surface to depth h gives P(h) − P₀ = ρ g h.
3. So P(h) = P₀ + ρ g h.
4. Pressure depends on depth h, not on the shape of the container.
_Source: syllabus Physics Ch 9 §9.3 Pressure due to a Fluid Column_
Keep practising Mechanical Properties of Solids and Fluids
Browse all Mechanical Properties of Solids and Fluids questions for AP Intermediate 1st Year, or explore more Physics topics.
Related questions
Poiseuille's law gives the volume flow rate Q of a viscous fluid through a horizontal pipeA solid object floats with 80 % of its volume submerged in water (ρ_water = 1000 kg m⁻³). Two soap bubbles of radii R₁ < R₂ are connected by a tube. Air flows:A liquid emerges from a hole at depth h below the free surface of a large open tank. The eThe height to which a liquid rises in a capillary tube of radius r is (with surface tensioThe excess pressure inside a spherical liquid drop of radius R and surface tension T is:Surface tension T of a liquid is best defined as:Reynolds number Re is dimensionless and given by Re = ρ v d / η, where d is a characterist