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Total kinetic energy of a body rolling without slipping is:
AJust ½ M v²_cm
BJust ½ I ω²
C½ M v²_cm + ½ I_cm ω²
DM v²_cm + I_cm ω²
Answer & Solution
Correct answer: C. ½ M v²_cm + ½ I_cm ω²
1. Pure rolling: motion = translation of CM + rotation about CM.
2. KE_trans = ½ M v²_cm.
3. KE_rot = ½ I_cm ω².
4. Total KE = ½ M v²_cm + ½ I_cm ω². Constraint v_cm = ω R links the two.
_Source: NCERT Class 11 Physics Ch 6 §6.13 Kinetic Energy of Rolling_
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