A solid disc and a hollow ring of the same mass and radius roll without slipping down the same incline. Reaching the bottom first will be:

1. For rolling without slipping, a = g sinθ / (1 + I/MR²). 2. Disc: I = ½MR² ⇒ a = g sinθ / 1.5. 3. Ring: I = MR² ⇒ a = g sinθ / 2. 4. Larger I/MR² gives smaller a. Disc has smaller I/MR², so it accelerates faster. 5. Hence the disc reaches the bottom first. _Source: NCERT Class 11 Physics Ch 6 §6.13 Rolling Motion_