A solid disc and a hollow ring of the same mass and radius roll without slipping down the same incline. Reaching the bottom first will be:
AThe solid disc
BThe hollow ring
CBoth at the same time
DDepends on mass
Answer & Solution
Correct answer: A. The solid disc
1. For rolling without slipping, a = g sinθ / (1 + I/MR²).
2. Disc: I = ½MR² ⇒ a = g sinθ / 1.5.
3. Ring: I = MR² ⇒ a = g sinθ / 2.
4. Larger I/MR² gives smaller a. Disc has smaller I/MR², so it accelerates faster.
5. Hence the disc reaches the bottom first.
_Source: syllabus Physics Ch 6 §6.13 Rolling Motion_
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