The equation of the straight line joining the points (2, 4) and (5, 6) is:

1. Slope between (2, 4) and (5, 6) is (6 − 4)/(5 − 2) = 2/3. 2. Point-slope form using (2, 4): y − 4 = (2/3)(x − 2). 3. Multiply through by 3: 3(y − 4) = 2(x − 2) → 3y − 12 = 2x − 4. 4. Rearrange to 2x − 3y + 8 = 0. 5. The point (11, 10) satisfies 22 − 30 + 8 = 0, confirming the equation. _Source: SCERT Kerala Std X Mathematics Part-2, Chapter 9-11 (pp 227-246, 2019 ed.)._