alleryThe equation of the straight line joining the points (2, 4) and (5, 6) is:
A2x − 3y + 8 = 0
Bx − 3y + 6 = 0
C3x − 2y + 2 = 0
Dx + y − 6 = 0
Answer & Solution
Correct answer: A. 2x − 3y + 8 = 0
1. Slope between (2, 4) and (5, 6) is (6 − 4)/(5 − 2) = 2/3.
2. Point-slope form using (2, 4): y − 4 = (2/3)(x − 2).
3. Multiply through by 3: 3(y − 4) = 2(x − 2) → 3y − 12 = 2x − 4.
4. Rearrange to 2x − 3y + 8 = 0.
5. The point (11, 10) satisfies 22 − 30 + 8 = 0, confirming the equation.
_Source: SCERT Kerala Std X Mathematics Part-2, Chapter 9-11 (pp 227-246, 2019 ed.)._
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