Compound A (C₃H₈O) on oxidation with strong K₂Cr₂O₇/H₂SO₄ gives an aldehyde, then carboxylic acid. A is:
APropan-1-ol (a primary alcohol)
BPropan-2-ol (a secondary alcohol → would give ketone, not acid)
CMethoxyethane (ether — does not oxidise to aldehyde)
DCannot decide
Answer & Solution
Correct answer: A. Propan-1-ol (a primary alcohol)
Primary alcohol → aldehyde → carboxylic acid (with strong oxidant like K₂Cr₂O₇/H₂SO₄). Secondary → ketone (no further oxidation under normal conditions). Ether C₃H₈O = CH₃-O-C₂H₅ — does not oxidise this way. So A is propan-1-ol.
Related questions
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