alleryIn SHM, when the displacement is half the amplitude (x = A/2), the ratio of KE to PE is:
A1 : 1
B2 : 1
C3 : 1
D4 : 1
Answer & Solution
Correct answer: C. 3 : 1
$KE = \frac{1}{2}m\omega^2(A^2 - x^2)$
$PE = \frac{1}{2}m\omega^2 x^2$.
At $x = A/2$: $KE \propto A^2 - A^2/4 = 3A^2/4$
$PE \propto A^2/4$. Ratio = 3:1.
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