alleryTotal mechanical energy of a particle in SHM (mass $m$, amplitude $A$, angular frequency $\omega$) is:
A$\frac{1}{2} m \omega A$
B$\frac{1}{2} m \omega^2 A^2$
C$m \omega^2 A^2$
D$\frac{1}{2} m \omega A^2$
Answer & Solution
Correct answer: B. $\frac{1}{2} m \omega^2 A^2$
$E = \frac{1}{2} m \omega^2 A^2$.
Constant throughout the motion.
At any point, $E = KE + PE = \frac{1}{2}m\omega^2(A^2 - x^2) + \frac{1}{2}m\omega^2 x^2$.
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