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The dehydration of ethanol with concentrated H₂SO₄ at 443 K gives:
AAcetaldehyde
BMethanol
CEthene (CH₂=CH₂)
DDiethyl ether
Answer & Solution
Correct answer: C. Ethene (CH₂=CH₂)
**Ethanol + conc. H₂SO₄ at 443 K → ethene** (intramolecular dehydration, E1 mechanism via protonated alcohol → carbocation → loss of β-H). At a *lower* temperature (~413 K), the product is **diethyl ether** (intermolecular dehydration, Williamson-type SN2-like).
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