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Among isomeric alcohols (e.g., butan-1-ol, butan-2-ol, 2-methylpropan-2-ol), boiling point order is:
ALinear primary > 2° branched > 3° (most branched lowest)
B3° > 2° > 1° (more substitution = higher bp)
CAll have identical bp because same molecular formula
D2° > 1° > 3°
Answer & Solution
Correct answer: A. Linear primary > 2° branched > 3° (most branched lowest)
**Linear (unbranched) alcohol has highest bp** because more surface area → stronger van der Waals contact. **Branching reduces surface area → lower bp**. So: **butan-1-ol > butan-2-ol > 2-methylpropan-2-ol (t-butanol)**.
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