A walks 5 km north, then 3 km east. The displacement from start (approx):
A3 km
B5 km
C8 km
D5.83 km
Answer & Solution
Correct answer: D. 5.83 km
1. Pythagoras: d = √(5² + 3²) = √34.
2. √34 ≈ 5.83 km.
3. Hence 5.83 km.
_Source: UGC NET Paper 1 Study Book (ugc-net.com class notes) — Direction Sense_
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