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If A walks at 4 km/h, he reaches office 10 min late. At 5 km/h, he is 10 min early. Distance to office:
A6.67 km
B5 km
C7.5 km
D10 km
Answer & Solution
Correct answer: A. 6.67 km
1. Let D = distance. Time at 4 = D/4 hours; at 5 = D/5 hours.
2. D/4 − D/5 = 20 min = 1/3 hour.
3. D/20 = 1/3 → D = 20/3 ≈ 6.67 km.
_Source: jkchrome TSD QB, p.3 — late-early pattern_
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