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Componendo and Dividendo combined: from a:b = c:d we get:

Aa:c = b:d
B(a+b):(c+d) = (a−b):(c−d)
Ca:b = (c+d):(c−d)
D(a+b):(a−b) = (c+d):(c−d)
Answer & Solution
Correct answer: D. (a+b):(a−b) = (c+d):(c−d)
1. Per OCR: "If a:b=c:d which implies a+b:a-b=c+d:c-d then...Componendo and Dividendo". 2. Powerful technique for solving ratio equations. 3. Direct application: if (x+3):(x-3) = 5:3, then 6x = 24 + 9 ⇒ x = 6. _Source: ICMAI BoS CMA Foundation Paper 3 (FBMS) — Paper3_07042026.pdf, Module 1 §1.1 (page 13)_
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Related questions
Dividendo operation on a:b = c:d gives:Componendo operation on a:b = c:d gives:If a:b = c:d, applying alternendo gives:If a:b = c:d, then b:a = d:c. This operation is termed: