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How many digits will be in the square root of a perfect square with EXACTLY 8 digits?
A3
B4
C5
D6
Answer & Solution
Correct answer: B. 4
For a perfect square with n digits: if n is even, its square root has n/2 digits; if n is odd, its square root has (n+1)/2 digits. With n = 8 digits, the square root has 8/2 = 4 digits. Example: √10000000 = ~3162.27, so √(11,000,000+) is a 4-digit number; the largest 8-digit perfect square is 99980001 = 9999², still a 4-digit root.
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