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A Pythagorean triplet has one member equal to 12, and the OTHER TWO members differ by 2. The triplet is:
A(12, 35, 37)
B(12, 5, 13)
C(6, 8, 12)
D(12, 13, 14)
Answer & Solution
Correct answer: A. (12, 35, 37)
Use the formula (2m, m² − 1, m² + 1) with 2m = 12, so m = 6. Then m² − 1 = 35 and m² + 1 = 37. The triplet (12, 35, 37) satisfies 12² + 35² = 144 + 1225 = 1369 = 37². The other two members (35 and 37) differ by 2, as required.
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