Home › UP Board Class 10 › mathematics › Circles › A chord of a circle of radius 10 cm subtends a r…
A chord of a circle of radius 10 cm subtends a right angle at the centre. The length of the chord is
A10 cm
B5 (square root of 2) cm
C20 cm
D10 (square root of 2) cm
Answer & Solution
Correct answer: D. 10 (square root of 2) cm
1. Chord with central angle 90 degrees forms an isosceles right triangle with two radii as legs.
2. Chord squared = 10 squared + 10 squared = 200.
3. Chord = 10 (square root of 2) cm.
_Source: NCERT Class 10 Mathematics, Ch 10 "Circles", §10.3_
Related questions
Two circles touch each other externally at P. A common tangent at P meets another common tIn a circle, two chords AB and CD intersect inside at P. If AP × PB = 8 and CP = 4, then PA point P is 25 cm away from the centre O of a circle and the tangent PT to the circle is Two parallel tangents are drawn to a circle of radius 8 cm. The distance between them isA tangent at point P of a circle of radius 5 cm is parallel to a chord 8 cm long. The distA circle touches all four sides of a quadrilateral ABCD with AB = 6, BC = 7, CD = 4. Then PA and PB are tangents from a point P to a circle. If angle APB = 90 degrees, the radius aA line drawn through the centre of a circle to bisect a chord is