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A chord of a circle of radius 10 cm subtends a right angle at the centre. The length of the chord is

A10 cm
B5 (square root of 2) cm
C20 cm
D10 (square root of 2) cm
Answer & Solution
Correct answer: D. 10 (square root of 2) cm
1. Chord with central angle 90 degrees forms an isosceles right triangle with two radii as legs. 2. Chord squared = 10 squared + 10 squared = 200. 3. Chord = 10 (square root of 2) cm. _Source: syllabus Mathematics, Ch 10 "Circles", §10.3_
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