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From the top of a 10 m tower, the angle of depression of an object on the ground is 60 degrees. The horizontal distance of the object from the foot of the tower is
A10/(square root of 3) m
B10 (square root of 3) m
C10 m
D5 m
Answer & Solution
Correct answer: A. 10/(square root of 3) m
1. tan(60) = 10/d, so d = 10/tan(60) = 10/(square root of 3).
2. Rationalize: d = 10 (square root of 3)/3.
3. Equivalent to 10/(square root of 3) m.
_Source: NCERT Class 10 Mathematics, Ch 9 "Some Applications of Trigonometry", §9.2_
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