Home › UP Board Class 10 › mathematics › Some Applications of Trigonometry › A 30 m high tower casts a shadow 30 m long. The …
A 30 m high tower casts a shadow 30 m long. The angle of elevation of the sun is
A30 degrees
B60 degrees
C45 degrees
D90 degrees
Answer & Solution
Correct answer: C. 45 degrees
1. tan(theta) = tower/shadow = 30/30 = 1.
2. theta = arctan(1) = 45 degrees.
3. Hence angle of elevation is 45 degrees.
_Source: NCERT Class 10 Mathematics, Ch 9 "Some Applications of Trigonometry", §9.2_
Related questions
From the top of a 7 m building, the angles of elevation of the top and angle of depressionThe shadow of a 30 m tall tower becomes 30/(square root of 3) m shorter when the sun risesFrom the top of a 10 m tower, the angle of depression of an object on the ground is 60 degA man standing on the deck of a ship 8 m above water level observes the angle of elevationThe angle of elevation of the top of a building from the bottom and top of a tower are 60 The angles of elevation of the top of a tower from two points A and B at distances of 4 m A tree breaks due to a storm and the broken part bends so that its top touches the ground An aeroplane at an altitude of 1500 m makes an angle of depression of 60 degrees with a fi