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In a right triangle with legs a and b, the altitude h drawn to the hypotenuse c satisfies
Ah = a + b - c
Bh = ab/c
Ch = (a + b)/2
Dh = c/2
Answer & Solution
Correct answer: B. h = ab/c
1. Area = 1/2 × a × b (using legs as base and height).
2. Area = 1/2 × c × h (using hypotenuse with altitude h).
3. Equate: ab = ch, so h = ab/c.
_Source: NCERT Class 10 Mathematics, Ch 6 "Triangles", §6.5_
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