If log 2 = 0.30103, log 80 = ?
A1.6020
B1.9030
C3.9030
D0.9580
Answer & Solution
Correct answer: B. 1.9030
1. log 80 = log(2³ × 10) = 3 log 2 + log 10.
2. = 3 × 0.30103 + 1 = 0.90309 + 1.
3. = 1.90309 ≈ 1.9030.
_Source: KMAT Karnataka 2023 PYQ Q.44_
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