A 60 kg milk container has 6 kg replaced with water, repeated twice more. Milk left is:

1. After each replacement, milk fraction multiplies by (60 − 6)/60 = 54/60 = 0.9. 2. After 3 replacements: milk = 60 × 0.9³ = 60 × 0.729 = 43.74. 3. Therefore 43.74 kg remains. _Source: KMAT Karnataka 2021 PYQ Q.40_