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Statement p ↔ q is equivalent to
Ap ∧ q
Bp ∨ q
C(p → q) ∧ (q → p)
D~p ∨ q
Answer & Solution
Correct answer: C. (p → q) ∧ (q → p)
1. The biconditional p ↔ q is true exactly when both have the same truth value.
2. This is equivalent to 'p implies q' AND 'q implies p'.
3. Hence p ↔ q ≡ (p → q) ∧ (q → p).
_Source: Maharashtra Balbharati Std XII Mathematics Part 1, Ch 1 "Mathematical Logic" §1.4_
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