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How long must a current of 5 A be passed to deposit 1 mole of silver from AgNO₃ (F = 96500 C/mol)?
A19300 s
B4825 s
C9650 s
D38600 s
Answer & Solution
Correct answer: A. 19300 s
1. Ag⁺ + e⁻ → Ag requires 1 mole of electrons per mole of Ag, i.e. 96500 C.
2. Q = I·t, so t = Q/I = 96500/5.
3. t = 19300 s ≈ 5.36 h.
_Source: Maharashtra Balbharati Std XII Chemistry, Ch 5 "Electrochemistry" §5.7_
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