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If E°(Cu²⁺/Cu) = +0.34 V and E°(Zn²⁺/Zn) = −0.76 V, the standard EMF of the Daniell cell is
A0.42 V
B−1.10 V
C1.10 V
D1.42 V
Answer & Solution
Correct answer: C. 1.10 V
1. E°_cell = E°_cathode − E°_anode.
2. Cu is cathode (higher reduction potential), Zn is anode.
3. E°_cell = 0.34 − (−0.76) = 1.10 V.
_Source: Maharashtra Balbharati Std XII Chemistry, Ch 5 "Electrochemistry" §5.4_
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