Home › Maharashtra HSC (Class 12) › Chemistry › Electrochemical Series › If E°(Cu²⁺/Cu) = +0.34 V and E°(Zn²⁺/Zn) = −0.76…
If E°(Cu²⁺/Cu) = +0.34 V and E°(Zn²⁺/Zn) = −0.76 V, the standard EMF of the Daniell cell is
A0.42 V
B−1.10 V
C1.10 V
D1.42 V
Answer & Solution
Correct answer: C. 1.10 V
1. E°_cell = E°_cathode − E°_anode.
2. Cu is cathode (higher reduction potential), Zn is anode.
3. E°_cell = 0.34 − (−0.76) = 1.10 V.
_Source: Maharashtra Balbharati Std XII Chemistry, Ch 5 "Electrochemistry" §5.4_
Related questions
The electrolytes of the two half-cells are joined by a:The two portions of a galvanic cell are also called:In the Daniell cell, zinc dissolves at the anode and copper:A negative standard potential marks a reducing agent that is:Going from top to bottom of the table, the electrode potential:The weakest oxidising agent in the table of potentials is:The most powerful reducing agent in aqueous solution is:The weakest reducing agent in the table of potentials is: