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Nernst equation at 25 °C for an electrode reaction n electrons transferred is
AE = E° + (0.0591/n) log Q
BE = E° − (0.0591/n) log Q
CE = E° − (n/0.0591) log Q
DE = E° / log Q
Answer & Solution
Correct answer: B. E = E° − (0.0591/n) log Q
1. The general Nernst equation is E = E° − (RT/nF) ln Q.
2. At 25 °C, converting natural log to base-10 gives factor 0.0591/n.
3. Thus E = E° − (0.0591/n) log Q.
_Source: Maharashtra Balbharati Std XII Chemistry, Ch 5 "Electrochemistry" §5.5_
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