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The relation between edge length a and radius r of an atom in BCC arrangement is
Aa = 2r
Ba = 4r/√2
Ca = r√3
Da = 4r/√3
Answer & Solution
Correct answer: D. a = 4r/√3
1. In BCC, atoms touch along the body diagonal of length √3 a.
2. Along this diagonal lie 4 atomic radii: √3 a = 4r.
3. Hence a = 4r/√3.
_Source: Maharashtra Balbharati Std XII Chemistry, Ch 1 "Solid State" §1.7_
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