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Energy stored in an inductor of inductance L carrying current I is
AL I²
BL I
C½ L I²
D½ L²I
Answer & Solution
Correct answer: C. ½ L I²
1. Building current from 0 to I requires work against the back-emf ε = L dI/dt.
2. Total work W = ∫₀^I L I dI = ½ L I².
3. This is stored as magnetic energy in the inductor.
_Source: Maharashtra Balbharati Std XII Physics, Ch 12 "Electromagnetic Induction" §12.7_
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