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If flux through a 100-turn coil changes from 0.01 Wb to 0.05 Wb in 0.02 s, the average induced emf is
A200 V
B20 V
C2 V
D0.2 V
Answer & Solution
Correct answer: A. 200 V
1. Change in flux per turn ΔΦ' = 0.05 − 0.01 = 0.04 Wb.
2. Total flux change linkage ΔΦ = NΔΦ' = 100 × 0.04 = 4 Wb-turn.
3. ε = ΔΦ/Δt = 4/0.02 = 200 V.
_Source: Maharashtra Balbharati Std XII Physics, Ch 12 "Electromagnetic Induction" §12.2_
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