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Energy stored in a 5 μF capacitor charged to 100 V is
A0.5 mJ
B25 mJ
C5 mJ
D50 mJ
Answer & Solution
Correct answer: B. 25 mJ
1. Energy U = ½ C V².
2. Substitute C = 5×10⁻⁶ F, V = 100 V.
3. U = ½ × 5×10⁻⁶ × 10⁴ = 25×10⁻³ J = 25 mJ.
_Source: Maharashtra Balbharati Std XII Physics, Ch 8 "Electrostatics" §8.7_
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