Two capacitors C₁ = 2 μF and C₂ = 3 μF are connected in series across a 10 V battery. The charge on each capacitor is

1. Series effective capacitance C_eq = C₁C₂/(C₁+C₂) = (2×3)/5 = 1.2 μF. 2. Charge supplied by the battery Q = C_eq × V = 1.2 × 10. 3. Q = 12 μC, and the same charge sits on every capacitor in a series chain. _Source: Maharashtra Balbharati Std XII Physics, Ch 8 "Electrostatics" §8.7_