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Two capacitors C₁ = 2 μF and C₂ = 3 μF are connected in series across a 10 V battery. The charge on each capacitor is
A12 μC
B6 μC
C30 μC
D20 μC
Answer & Solution
Correct answer: A. 12 μC
1. Series effective capacitance C_eq = C₁C₂/(C₁+C₂) = (2×3)/5 = 1.2 μF.
2. Charge supplied by the battery Q = C_eq × V = 1.2 × 10.
3. Q = 12 μC, and the same charge sits on every capacitor in a series chain.
_Source: Maharashtra Balbharati Std XII Physics, Ch 8 "Electrostatics" §8.7_
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