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Capacitance of a parallel-plate capacitor with plate area A, separation d and a dielectric of constant K is
Aε₀A/d
Bε₀A/(Kd)
CKA/(ε₀d)
DKε₀A/d
Answer & Solution
Correct answer: D. Kε₀A/d
1. Without dielectric C₀ = ε₀A/d.
2. Inserting a dielectric multiplies the field-suppressing capacity by K.
3. Hence C = Kε₀A/d.
_Source: Maharashtra Balbharati Std XII Physics, Ch 8 "Electrostatics" §8.6_
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