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Electric field at a point INSIDE a uniformly charged spherical shell is
Aq/(4πε₀r²)
Bzero
Cσ/ε₀
Dinfinite
Answer & Solution
Correct answer: B. zero
1. Apply Gauss' law to a concentric spherical Gaussian surface of radius r < R.
2. No charge is enclosed by this inner surface (all charge lies on shell at radius R).
3. Hence E·4πr² = 0/ε₀, giving E = 0 inside the shell.
_Source: Maharashtra Balbharati Std XII Physics, Ch 8 "Electrostatics" §8.2.1_
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