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Gauss' law in electrostatics relates the closed-surface flux of electric field to the
Atotal enclosed charge divided by ε₀
Baverage field on the surface
Cpotential at the centre
Dsurface area only
Answer & Solution
Correct answer: A. total enclosed charge divided by ε₀
1. Gauss' law states ∮ E·dS = q_enc / ε₀ over a closed Gaussian surface.
2. Here q_enc is the total charge enclosed by the surface and ε₀ is the permittivity of free space.
3. Only the enclosed charge contributes; external charges cancel out.
_Source: Maharashtra Balbharati Std XII Physics, Ch 8 "Electrostatics" §8.1_
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