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A wheel of moment of inertia 2 kg·m² is accelerated from rest to 60 rad/s in 10 s. The torque applied is

A12 N·m
B60 N·m
C6 N·m
D30 N·m
Answer & Solution
Correct answer: A. 12 N·m
1. Angular acceleration α = Δω/Δt = 60/10 = 6 rad/s². 2. Torque τ = Iα. 3. τ = 2 × 6 = 12 N·m. _Source: Maharashtra Balbharati Std XII Physics, Ch 1 "Rotational Dynamics" §1.7_
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