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A force increases the speed of a 1.0 kg object from 4 m/s to 8 m/s. The work done by the force is:
A8 J
B24 J
C32 J
D16 J
Answer & Solution
Correct answer: B. 24 J
1. Work done = change in kinetic energy = (1/2)m(v^2 - u^2).
2. = (1/2)(1.0)(8^2 - 4^2) = (1/2)(64 - 16).
3. = (1/2)(48) = 24 J.
_Source: RRB Group D CEN-02/2018 PYQ, Q.50._
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