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A constant force acts on an 8 kg object for 3 s, increasing its velocity from 4 m/s to 6 m/s. What is the magnitude of the force?
A4.33 N
B6.33 N
C5.33 N
D3.33 N
Answer & Solution
Correct answer: C. 5.33 N
1. Acceleration a = (6 − 4) / 3 = 2/3 m/s².
2. Force F = m × a = 8 × 2/3.
3. F = 16/3 ≈ 5.33 N.
_Source: RRB Group D CEN-02/2018 PYQ, Q.36._