allery5 ସାଙ୍ଗମାନଙ୍କ ମଧ୍ୟରେ ଏକ କେକ୍ ଅଂଶୀଦାର | ସେମାନଙ୍କ ମଧ୍ୟରୁ ଚାରିଜଣ ଯଥାକ୍ରମେ 1/8, 1/6, 5/12 ଏବଂ 1/12 ପିଠା ନିଅନ୍ତି | ପଞ୍ଚମ ବନ୍ଧୁ କେଉଁ ଅଂଶ ପାଆନ୍ତି?
A9/24
B4/24
C5/24
D6/24
Answer & Solution
Correct answer: C. 5/24
1. LCD 24 ନେଲେ ଚାରି ଅଂଶର ଯୋଗଫଳ = 3/24 + 4/24 + 10/24 + 2/24 = 19/24।
2. ଅବଶିଷ୍ଟ ଅଂଶ = 1 - 19/24।
3. = 5/24।
_Source: RRB Group D CEN-02/2018 PYQ, Q.64._
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