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Among methyl chloride, methyl bromide and methyl iodide, the order of boiling points is:
ACH₃I > CH₃Br > CH₃Cl
BCH₃Cl > CH₃Br > CH₃I
CCH₃Br > CH₃I > CH₃Cl
DCH₃Cl = CH₃Br = CH₃I
Answer & Solution
Correct answer: A. CH₃I > CH₃Br > CH₃Cl
Boiling point increases with molecular mass and polarisability (van der Waals forces): **R-I > R-Br > R-Cl > R-F** for the same R group. Heavier halogen = larger atom = more polarisable = stronger dispersion forces.
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