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The reaction of alkyl chloride/bromide with NaI in dry acetone to form alkyl iodide is called:
AWurtz reaction
BFinkelstein reaction
CSwarts reaction
DSandmeyer reaction
Answer & Solution
Correct answer: B. Finkelstein reaction
**Finkelstein reaction**: R-X + NaI → R-I + NaX (X = Cl, Br) in **dry acetone**. NaCl/NaBr precipitates out (insoluble in acetone) → drives equilibrium forward via Le Chatelier. **Swarts reaction** (R-X + AgF → R-F) makes fluorides.
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