alleryযদি x3339 সংখ্যাটো 11 দ্বাৰা বিভাজ্য হয়, তেন্তে x অংকটো কিমান?
A2
B4
C5
D3
Answer & Solution
Correct answer: C. 5
1. 11 দ্বাৰা বিভাজ্যতা: (অযুগ্ম স্থানৰ অংকবোৰৰ যোগফল) - (যুগ্ম স্থানৰ অংকবোৰৰ যোগফল) 11-ৰ এটা গুণিতক হ’ব লাগিব।
2. x3339-ৰ বাবে, সোঁফালৰ পৰা: অযুগ্ম স্থানৰ অংকসমূহ 9, 3, x; যুগ্ম স্থানৰ অংকসমূহ 3, 3। অযুগ্ম স্থানৰ যোগফল = 12 + x, যুগ্ম স্থানৰ যোগফল = 6।
3. পাৰ্থক্য = 6 + x। বিভাজ্যতাৰ বাবে, 6 + x = 11, গতিকে x = 5।
_Source: RRB Group D CEN-02/2018 PYQ, Q.71._
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