The age of a mother 10 years ago was thrice her son's age. 10 years hence, her age will be twice her son's. The ratio of their present ages is:
A12 : 5
B6 : 1
C7 : 3
D5 : 2
Answer & Solution
Correct answer: C. 7 : 3
1. Let present ages be M and S. Then M - 10 = 3(S - 10), so M = 3S - 20.
2. Also M + 10 = 2(S + 10), so M = 2S + 10.
3. 3S - 20 = 2S + 10 gives S = 30, M = 70. Ratio = 70 : 30 = 7 : 3.
_Source: RRB Group D CEN-02/2018 PYQ, Q.46._
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