alleryایک پہیہ 22 km کا فاصلہ 2500 گردشوں میں طے کرتا ہے۔ وہیل کا قطر کیا ہے؟ (لیے π = 22/7)
A2.8 m
B1.4 m
C5.6 m
D3.5 m
Answer & Solution
Correct answer: A. 2.8 m
1۔
فاصلہ فی انقلاب = کل فاصلہ / انقلابات = 22000 m / 2500 = 8.8 m
2۔
یہ فریم کے برابر ہے، لہذا πd = 8.8، d = 8.8 × 7/22 دینا۔
3۔
d = 61.6/22 = 2.8 m
_ماخذ: RRB گروپ D (RRC) PYQ، منعقد ہوا 27-10-2013, Q.99._
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