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ଏକ ଚକ 2500 ଥର ଘୂରି 22 km ଦୂରତା ଅତିକ୍ରମ କରେ। ଚକର ବ୍ୟାସ କେତେ? (π = 22/7 ନିଅନ୍ତୁ)

A2.8 m
B1.4 m
C5.6 m
D3.5 m
Answer & Solution
Correct answer: A. 2.8 m
1. ପ୍ରତି ଘୂର୍ଣ୍ଣନରେ ଦୂରତା = ମୋଟ ଦୂରତା / ଘୂର୍ଣ୍ଣନ ସଂଖ୍ୟା = 22000 m / 2500 = 8.8 m। 2. ଏହା ପରିଧି ସହ ସମାନ, ତେଣୁ πd = 8.8 ରୁ d = 8.8 × 7/22। 3. d = 61.6/22 = 2.8 m। _Source: RRB Group D (RRC) PYQ, held 27-10-2013, Q.99._
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