alleryएक चाक 2500 आवर्तनांमध्ये 22 km अंतर पार करते. चाकाचा व्यास किती आहे? (घ्या π = 22/7)
A2.8 m
B1.4 m
C5.6 m
D3.5 m
Answer & Solution
Correct answer: A. 2.8 m
1.
प्रति क्रांती अंतर = एकूण अंतर / क्रांती = 22000 m / 2500 = 8.8 मी.
2.
हे परिघाच्या बरोबरीचे आहे, म्हणून πd = 8.8, d = 8.8 × 7/22 देत.
3.
d = 61.6/22 = 2.8 मी.
_स्रोत: RRB ग्रुप D (RRC) PYQ, आयोजित 27-10-2013, Q.99._
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