alleryहें . एक चाक 2500 क्रांतींत 22 km अंतराचेर वता. चाकाचो व्यास कितलो आसता? (π = 22/7 घेवचें)
A2.8 m
B1.4 m
C5.6 m
D3.5 m
Answer & Solution
Correct answer: A. 2.8 m
हें .
1 हें नांव.
दर क्रांतीचें अंतर = एकूण अंतर / क्रांती = 22000 m / 2500 = 8.8 मी.
2 हें नांव.
हें परिघाच्या बरोबर आसता, देखून πd = 8.8, d = 8.8 × 7/22 मेळटा.
3 हें नांव.
d = 61.6/22 = 2.8 मी.
_स्रोत: आरआरबी गट D (आरआरसी) पीवायक्यू, 27-10-2013, Q.99._ जाल्लें.
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