alleryએક પૈડું 2500 પરિભ્રમણમાં 22 kmનું અંતર કાપે છે. વ્હીલનો વ્યાસ કેટલો છે? (લો π = 22/7)
A2.8 m
B1.4 m
C5.6 m
D3.5 m
Answer & Solution
Correct answer: A. 2.8 m
1.
પ્રતિ ક્રાંતિ = કુલ અંતર / ક્રાંતિ = 22000 m / 2500 = 8.8 m.
2.
આ પરિઘ બરાબર છે, તેથી πd = 8.8, આપીને d = 8.8 × 7/22.
3.
d = 61.6/22 = 2.8 મી.
_સ્રોત: RRB ગ્રુપ D (RRC) PYQ, યોજાયેલ 27-10-2013, Q.99._
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