alleryএটা চকা 2500 ঘূৰ্ণনত 22 কিলোমিটাৰ দূৰত্ব অতিক্ৰম কৰে। চকাৰ ব্যাস কিমান? (π = 22/7 লওক)
A2.8 m
B1.4 m
C5.6 m
D3.5 m
Answer & Solution
Correct answer: A. 2.8 m
1।
প্ৰতি বিপ্লৱৰ দূৰত্ব = মুঠ দূৰত্ব / বিপ্লৱ = 22000 m / 2500 = 8.8 মি.
2।
ই পৰিধিৰ সমান হয়, গতিকে πd = 8.8, যাৰ ফলত d = 8.8 × 7/22 পোৱা যায়।
3।
d = 61.6/22 = 2.8 মি.
_উৎস: আৰ আৰ বি গ্ৰুপ D (আৰ আৰ চি) পি ৱাই কিউ, অনুষ্ঠিত 27-10-2013, Q.99._
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